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HuagongsheHuagongshe Chemie-Druckbericht · Nur für Forschungszwecke
HRID 2280365Erstellt: 24. Oktober 2026

Iodine → 1~4~-Iodo-1~1~,2~1~:2~3~,3~1~-terphenyl

https://huagongshe.com/de/reaction/2280365

Reaktionsgleichung

Beteiligte Stoffe

RolleNameHCIDEinwaage
EduktIodineHCID 807—
EduktSulfuric AcidHCID 1118—
EduktM-TerphenylHCID 7076—
EduktHydroiodic acid dihydrateHCID 85613701—
LösungsmittelAcetic AcidHCID 176—
LösungsmittelMethanolHCID 887—
Produkt1~4~-Iodo-1~1~,2~1~:2~3~,3~1~-terphenylHCID 12378402—
Produkt5'-Iodo-m-terphenylHCID 13067230—

Reaktionsschritte

A three-necked flask was charged with 250 g of m-terphenyl (ALDRICH), 50 g of hydroiodic acid dihydrate, 75 g of iodine, 750 ml of acetic acid, and 25 ml of concentrated sulfuric acid, and reaction was allowed to proceed at 70° C. for 3 hours. The product was poured into 5 L of methanol and the mixture was stirred for 1 hour and filtrated. The obtained crystals were purified by column chromatography, and recrystallized from acetonitrile to give 64 g of 3′-phenyl-4-iodobiphenyl (Intermediate 4) and 17 g of 3-phenyl-5-iodobiphenyl in the form of white powder. FD-MS and H-NMR analysis identified the powder as Intermediate 4.

Herkunft & Nachweise

DOI10.6084/m9.figshare.5104873.v1
PatentnummerUS09139522B2
Quelldatensatzuspto-grants-2015_09
ORD IDord-a4026af5f96145e1a1263c9b7eb65129
Quellennotizuspto-grants-2015_09