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HuagongsheHuagongshe Chemie-Druckbericht · Nur für Forschungszwecke
HRID 56067Erstellt: 24. Oktober 2026

Methyl iodide → 1-Fluoro-4-(2-methoxyethyl)benzene

https://huagongshe.com/de/reaction/56067

Reaktionsgleichung

Beteiligte Stoffe

RolleNameHCIDEinwaage
EduktMethyl iodideHCID 6328—
EduktSodium hydrideHCID 24758—
EduktAmmonium ChlorideHCID 25517—
Edukt4-Fluorophenethyl AlcoholHCID 82068—
LösungsmittelTetrahydrofuranHCID 8028—
Produkt1-Fluoro-4-(2-methoxyethyl)benzeneHCID 5714305945,2%

Reaktionsbedingungen

Temperatur60 °C

Reaktionsschritte

Sodium hydride (60% dispersion in mineral oil, 145 mg, 3.62 mmol) was slowly added to a solution of 4-fluorophenethyl alcohol (338 mg, 2.41 mmol) in THF (5 mL) at room temperature and with stirring. At the end of the addition, the solution had become cloudy. The reaction mixture was heated to 60° C. for 2 h and then cooled to 0° C. Iodomethane (225 μL, 3.62 mmol) was slowly added to the solution and the reaction mixture was stirred overnight. Upon the completion of the reaction, the mixture was cooled to 0° C., neutralized with aq. sat. NH4Cl (25 mL) and extracted with EtOAc (3×25 mL). The combined extracts were sequentially washed with aq. sat. NH4Cl (3×20 mL), brine (20 mL) and dried (Na2SO4). The crude product was concentrated and dried over high vacuum. Chromatography of the residue (EtOAc/hexanes=1/3) gave 169 mg (1.09 mmol) of the title product. Yield: 45%, pale yellow oil. 1H NMR (300 MHz, CDCl3): δ 7.18 (dd, J=8.5, 5.6, Hz, 2H), 6.98 (apparent t, J=8.7 Hz, 2H), 3.58 (t, J=6.9 Hz, 2H), 3.36 (s, 3H), 2.86 (t, J=6.9 Hz, 2H) ppm. 13C NMR (75 MHz, CDCl3): δ 161.7 (d, J=242.2 Hz), 134.8 (d, J=3.2 Hz), 130.4 (d, J=7.7 Hz), 115.3 (d, J=20.9 Hz), 73.7, 58.8, 35.5 ppm. 19F NMR (282 MHz, CDCl3): δ −113.3 (m) ppm.

Herkunft & Nachweise

DOI10.6084/m9.figshare.5104873.v1
PatentnummerUS09434699B2
Quelldatensatzuspto-grants-2016_09
ORD IDord-afdc75e778eb488ca701bf91109dbe65
Quellennotizuspto-grants-2016_09