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Huagongshe화공사 화학 정보 인쇄 보고서 · 연구 참고용
HRID 11014생성일: 2026년 10월 24일

Triethylamine → 4-Amino-9-methoxypyrrolo[3,4-c]carbazole-1,3(2H,6H)-dione

https://huagongshe.com/ko/reaction/11014

반응식

참여 물질

역할이름HCID투입량
반응물TriethylamineHCID 8471—
반응물P,P-Diphenylphosphinic azideHCID 199401—
반응물9-Methoxy-1,3-dioxo-1,2,3,6-tetrahydropyrrolo[3,4-c]carbazole-4-carboxylic acidHCID 11843005—
용매tert-ButanolHCID 6386—
용매Trifluoroacetic acid methylene chlorideHCID 21863450—
생성물4-Amino-9-methoxypyrrolo[3,4-c]carbazole-1,3(2H,6H)-dioneHCID 1184300693.4%

반응 단계

Diphenylphosphoryl azide (1.81 mL, 8.38 mmol) was added to a mixture of the 9-methoxy-1,3-dioxo-1,2,3,6-tetrahydropyrrolo[3,4-c]carbazole-4-carboxylic acid (2.55 g, 8.22 mmol), prepared as in example 4, and Et3N (1.17 mL, 8.38 mmol) in anhydrous t-butanol (300 mL) and the mixture was refluxed under an atmosphere of nitrogen for 16 h. The solution was concentrated in vacuo and the residue partitioned between EtOAc and saturated aqueous NaHCO3. Insoluble material was removed by filtration of the two layers through Celite, washing through with more EtOAc. The organic phase was dried, the drying agent was removed and the solution was concentrated to dryness and gave a yellow solid. This material was dissolved in CH2Cl2/trifluoroacetic acid (1:1) (200 mL) and the solution was held at room temperature for 1 h. After concentration in vacuo the residue was partitioned between EtOAc and saturated aqueous NaHCO3 solution. The EtOAc solution was dried, the drying agent was removed and the solution was concentrated to dryness to give an orange solid which was adsorbed onto silica and chromatographed. Elution with ethyl acetate/petroleum ether (1:1) followed by ethyl acetate and then methanol/ethyl acetate (1:9) gave 4-amino-9-methoxypyrrolo[3,4-c]carbazole-1,3(2H,6H)-dione (6) as an orange powder (2.16 g, 93%), mp 342–345° C. 1H NMR δ [(CD3)2SO] 11.18 (s, 1H), 10.78 (br s, 1H), 8.18 (d, J=2.5 Hz, 1H), 7.29 (d, J=8.7 Hz, 1H), 7.01 (dd, J=8.7, 2.5 Hz, 1H), 6.83 (s, 1H), 6.28 (br s, 2H), 3.82 (s, 3H). Found: C, 63.05; H, 3.99; N, 14.05. C15H11N3O3, 1/2H2O requires C, 63.04; H, 4.06; N, 14.7.

출처 및 근거

DOI10.6084/m9.figshare.5104873.v1
특허 번호US07094798B1
출처 데이터셋uspto-grants-2006_08
ORD IDord-a73b7af270cf42e6b11cc84eb5367f8f
출처 메모uspto-grants-2006_08