Iodine → 6-Fluoro-2-iodopyridin-3-ol

참여 물질

반응 단계

6-Fluoro-3-hydroxypyridine (870 mg) and iodine (9.76 g) were dissolved in a mixed solvent composed of methanol (20 ml) and water (10 ml) to prepare a solution which was then stirred at room temperature for 120 hr. Thereafter, sodium sulfite was added until the solution became transparent. Methanol in the reaction solution was removed under the reduced pressure, water was added to the residue, and the mixture was extracted with chloroform. The chloroform layer was washed with water and saturated brine and was dried over anhydrous magnesium sulfate. The solvent was removed by distillation under the reduced pressure, and the residue was purified by column chromatography using acetone-chloroform to give 6-fluoro-2-iodo-pyridin-3-ol (350 mg, yield 19%).

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