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Huagongshe화공사 화학 정보 인쇄 보고서 · 연구 참고용
HRID 276285생성일: 2026년 10월 24일

Triphenylphosphine → 1-Cyclopentylamino-1-(thioacetylmethyl)cyclopentane

https://huagongshe.com/ko/reaction/276285

반응식

참여 물질

역할이름HCID투입량
반응물TriphenylphosphineHCID 11776—
반응물2-Thiopheneacetic acidHCID 15970—
반응물Diisopropyl diazene-1,2-dicarboxylateHCID 75555—
반응물[1-(Cyclopentylamino)cyclopentyl]methanolHCID 18316183—
용매TetrahydrofuranHCID 8028—
생성물1-Cyclopentylamino-1-(thioacetylmethyl)cyclopentaneHCID 18316049103.3%

반응 단계

To a 0° C. solution of Ph3P (27.9 g, 0.107 mol, 1.3 equiv.) in anh. THF (400 mL) were successively added diisopropyl azodicarboxylate (21.5 g, 0.107 mol, 1.3 equiv.) and 1-cyclopentylamino-1-(hydroxymethyl)cyclopentane (Method B4d; 15.0 g, 0.082 mol). The resulting slurry was stirred for 30 min., then was treated with thiolacetic acid (7.6 mL, 0.107 mol, 1.3 equiv.). The resulting yellow solution was stirred for 15 min. and concentrated under reduced pressure to about 100 mL. The residue was dissolved in EtOAc (200 mL) and the resulting solution was extracted with a 1N HCl solution (5×125 mL). The combined aqueous layers were washed with EtOAc (2×200 mL), neutralized with K2CO3 to pH 7.0-7.5, then extracted with EtOAc (5×200 mL). The organic layers were combined, dried (Na2SO4) and concentrated under reduced pressure. The residue was dried in vacuo to afford 1-cyclopentylamino-1-(thioacetylmethyl)cyclopentane as a yellow oil (19.1 g): TLC (10% EtOAc/hexanes) Rf0.16; 1H NMR (CDCl3) δ1.20-1.87 (m, 16H), 2.34 (s, 3H), 2.92-3.02 (m, 1H), 3.15 (s, 2H); 13C NMR (CDCl3) δ23.9, 25.2, 29.3, 36.4, 40.1, 55.8, 73.0, 169.8; CI-LRMS m/z (rel abundance) 242 ((M+H)+, 100%).

출처 및 근거

DOI10.6084/m9.figshare.5104873.v1
특허 번호US06353006B1
출처 데이터셋uspto-grants-2002_03
ORD IDord-df67ef90cee042e5bdf266606b78d7b4
출처 메모uspto-grants-2002_03