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Huagongshe화공사 화학 정보 인쇄 보고서 · 연구 참고용
HRID 7488생성일: 2026년 10월 24일

Hydrochloric Acid → 4-(2-Fluoro-5-hydroxy-4-methylanilino)-6-methoxy-7-[(2-methylthiazol-4-yl)methoxy]cinnoline hydrochloride

https://huagongshe.com/ko/reaction/7488

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참여 물질

역할이름HCID투입량
반응물Hydrochloric AcidHCID 313—
반응물5-Amino-4-fluoro-2-methylphenolHCID 10154098—
반응물4-Chloro-6-methoxy-7-[(2-methylthiazol-4-yl)methoxy]cinnolineHCID 21991061—
용매IsopropanolHCID 3776—
용매2-PentanolHCID 22386—
생성물4-(2-Fluoro-5-hydroxy-4-methylanilino)-6-methoxy-7-[(2-methylthiazol-4-yl)methoxy]cinnoline hydrochlorideHCID 2199102889.2%

반응 단계

A suspension of 4-chloro-6-methoxy-7-[(2-methylthiazol-4-yl)methoxy]cinnoline (150 mg, 0.46 mmol) and 2-fluoro-5-hydroxy-4-methylaniline (78 mg, 0.56 mmol), (prepared as described for the starting material in Example 11), in 2-pentanol (3 ml) and a 5M solution of hydrogen chloride in isopropanol (105 μl) was heated at reflux for 90 minutes. The solid obtained was filtered off, washed with isopropanol followed by ether to give 4-(2-fluoro-5-hydroxy-4-methylanilino)-6-methoxy-7-[(2-methylthiazol-4-yl)methoxy]cinnoline hydrochloride as a pale yellow solid (190 mg, 82%).

출처 및 근거

DOI10.6084/m9.figshare.5104873.v1
특허 번호US07087602B2
출처 데이터셋uspto-grants-2006_08
ORD IDord-0e7581b52af94d42a3848dfce08231a1
출처 메모uspto-grants-2006_08