HRID1055727
反应详情
EQUATION
反应方程式
REACTANTS
反应物
PRODUCTS
生成物
PROCEDURE
实验过程
50 mg (0.17 mmol) of the compound of Example 6A and 52.9 mg (0.17 mmol) of the compound of Example 19A were reacted and worked up analogously to the procedure of Example 19. This gave 49 mg (49% of theory) of the title compound.