反应详情

Analogously to the process described in Example 96, 100 mg (0.341 mmol) of the compound of Example 70A and 110 mg (0.341 mmol, 85% pure) of the compound from Example 23A gave 52 mg (28% of theory) of the title compound. Here, purification was by preparative HPLC according to Method 33, and final trituration of the product could be dispensed with.