反应详情

As in Example 1, Part C, 4.46 g (0.024 mole) of 2-cyclopropyl-5-methoxy-1H-indole was treated with 15 mL (0.024 mol) of a 1.6M solution of n-butyl lithum in hexane, 24 ml (0.024 mol) of a 1M solution of ZnCl2 in ether, and 12.27 mL (0.024 mol) of methyl 2-bromoacetate to give after chromatography on silica gel (5% EtOAc/toluene→15% EtOAc/toluene) 3.81 g (61%) of 2-cyclopropyl-5-methoxy-1H-indole-3-acetic acid methyl ester as an oil.