HRID1266115

反应详情

EQUATION

反应方程式

HRID 1266115 的结构方程式

PROCEDURE

实验过程

The title compound (0.16 g, 42%) was prepared by the general method of Example 402 from (7aR,11aS)-5,6,7a,8,9,10,11,11a-octahydro-4H-pyrido[3′,4′:4,5]pyrrolo[3,2,1-ij]quinoline (0.21 g, 1.0 mmol), 4-chloro-4′-fluorobutyrophenone (0.40 g, 2.0 mmol), KI (catalytic) and K2CO3 (0.28 g, 2.0 mmol) after chromatographic purification as a white amorphous solid. The 1H NMR was identical to that of Example 402, 4-((7aS,11aR)-5,6,8,9,11,11a-hexahydro-4H-pyrido[3′,4′:4,5]pyrrolo[3,2,1-ij]quinolin-10(7aH)-yl)-1-(4-fluorophenyl)-1-butanone

WORKUP

后处理

  1. customafter chromatographic purification as a white amorphous solid