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HRID1401024

反应详情

EQUATION

反应方程式

HRID 1401024 的结构方程式

REACTANTS

反应物

2
结构：C=C(C)[C@@H]1CC[C@]2(N)CC[C@]3(C)[C@H](CC[C@@H]4[C@@]5(C)CC=C(OS(=O)(=O)C(F)(F)F)C(C)(C)[C@@H]5CC[C@]43C)[C@@H]12
HCID71698571

未命名化合物

结构：CCOC(=O)C1=C(C)C=C(B2OC(C)(C)C(C)(C)O2)CC1
HCID86692380

未命名化合物

PRODUCTS

生成物

1
结构：C=C(C)[C@@H]1CC[C@]2(N)CC[C@]3(C)[C@H](CC[C@@H]4[C@@]5(C)CC=C(C6=CC(C)=C(C(=O)OCC)CC6)C(C)(C)[C@@H]5CC[C@]43C)[C@@H]12
HCID86692381

未命名化合物

PROCEDURE

实验过程

The title compound was prepared following the method for the preparation of Example 1, Step 1 described above, using (1R,3aS,5aR,5bR,7aR,11aR,11bR,13aR,13bR)-3a-amino-5a,5b,8,8,11a-pentamethyl-1-(prop-1-en-2-yl)-2,3,3a,4,5,5a,5b,6,7,7a,8,11,11a,11b,12,13,13a,13b-octadecahydro-1H-cyclopenta[a]chrysen-9-yl trifluoromethanesulfonate and ethyl 2-methyl-4-(4,4,5,5-tetramethyl-1,3,2-dioxaborolan-2-yl)cyclohexa-1,3-dienecarboxylate as reactants. MS: m/e 557.4 (M−16)+, 2.47 min (method 2). 1H NMR (400 MHz, CHLOROFORM-d) δ 5.65 (s, 1H), 5.28 (d, J=5.8 Hz, 1H), 4.72 (s, 1H), 4.59 (s, 1H), 4.25-4.16 (m, 2H), 2.62-2.48 (m, 1H), 2.48-2.34 (m, 2H), 2.31-2.17 (m, 2H), 2.15 (s, 3H), 2.09-1.97 (m, 2H), 1.80-1.35 (m, 17H), 1.35-1.18 (m, 9H), 1.18-1.04 (m, 6H), 1.02-1.00 (s, 3H), 0.96 (s, 3H), 0.89 (s, 3H).

WORKUP

后处理

  1. customfor the preparation of Example 1, Step 1
  2. customm/e 557.4 (M−16)+, 2.47 min (method 2)