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HRID1401037

反应详情

EQUATION

反应方程式

HRID 1401037 的结构方程式

REACTANTS

反应物

2
结构：C=C(C)[C@@H]1CC[C@]2(N)CC[C@]3(C)[C@H](CC[C@@H]4[C@@]5(C)CC=C(OS(=O)(=O)C(F)(F)F)C(C)(C)[C@@H]5CC[C@]43C)[C@@H]12
HCID71698571

未命名化合物

结构：COC(=O)C1=CC=C(B2OC(C)(C)C(C)(C)O2)CC1
HCID86692396

未命名化合物

PRODUCTS

生成物

1
结构：C=C(C)[C@@H]1CC[C@]2(N)CC[C@]3(C)[C@H](CC[C@@H]4[C@@]5(C)CC=C(C6=CC=C(C(=O)OC)CC6)C(C)(C)[C@@H]5CC[C@]43C)[C@@H]12
HCID86692397

未命名化合物

收率 60.8%

PROCEDURE

实验过程

The title compound was prepared following the method described in step 1 for the preparation of Example 1, using (1R,3aS,5aR,5bR,7aR,11aR,11bR,13aR,13bR)-3a-amino-5a,5b,8,8,11a-pentamethyl-1-(prop-1-en-2-yl)-2,3,3a,4,5,5a,5b,6,7,7a,8,11,11a,11b,12,13,13a,13b-octadecahydro-1H-cyclopenta[a]chrysen-9-yl trifluoromethanesulfonate and methyl 4-(4,4,5,5-tetramethyl-1,3,2-dioxaborolan-2-yl)cyclohexa-1,3-dienecarboxylate as the reactants. (60.8% yield). MS: m/e 529.5 (M−16)+, 2.816 min (method 8). 1H NMR (400 MHz, CHLOROFORM-d) δ 6.99 (d, J=5.8 Hz, 1H), 5.78 (d, J=5.8 Hz, 1H), 5.27 (dd, J=6.0, 1.8 Hz, 1H), 4.70 (d, J=2.0 Hz, 1H), 4.57 (d, J=1.3 Hz, 1H), 3.72 (s, 3H), 2.52 (td, J=10.8, 5.3 Hz, 1H), 2.48-2.39 (m, 1H), 2.36-2.29 (m, 1H), 2.09-1.95 (m, 2H), 1.76-1.20 (m, 22H), 1.66 (s, 3H), 1.05 (s, 3H), 0.98 (s, 3H), 0.94 (s, 6H), 0.86 (s, 3H).

WORKUP

后处理

  1. customdescribed in step 1 for the preparation of Example 1
  2. customm/e 529.5 (M−16)+, 2.816 min (method 8)