HRID1441446

反应详情

EQUATION

反应方程式

HRID 1441446 的结构方程式

PROCEDURE

实验过程

The product of Example 9A (198 mg, 0.826 mmol) was coupled with the product of Example 48A (345 mg, 1.11 mmol) according to the procedure of Example 26B. The title product was purified by preparative HPLC (column: Xterra™ RP-18, 5 μm, 30×100 mm; eluting solvent, NH4HCO3—NH4OH/H2O (PH=10), (v. 90/10 to 10/90 over 20 min.); flow rate, 40 mL/min.; uv, 254 nm) to provide a solid (79.7 mg, yield, 24.8%). 1H NMR (300 MHz, CD3OD) δ 1.50-1.93 (m, 3H) 1.99-2.15 (m, 1H) 2.29-2.37 (m, 1H) 2.78-3.05 (m, 5H) 3.49 (ddd, J=14.83, 8.39, 1.86 Hz, 1H) 5.27-5.36 (m, 1H) 7.01 (s, 1H) 7.27 (d, J=9.49 Hz, 1H) 7.59 (d, J=8.81 Hz, 1H) 7.94 (dd, J=8.81, 1.70 Hz, 1H) 8.11 (d, J=9.15 Hz, 1H) 8.24 (s, 1H) ppm. MS (DCI/NH3) m/z 389 (M+H)+. Anal. Calculated for C20H19F3N4O: C, 61.85; H, 4.93; N, 14.43. Found: C, 61.62; H, 4.56; N, 13.89.

WORKUP

后处理

  1. customThe title product was purified by preparative HPLC (column: Xterra™ RP-18, 5 μm, 30×100 mm; eluting solvent, NH4HCO3—NH4OH/H2O (PH=10), (v. 90/10 to 10/90 over 20 min.); flow rate, 40 mL/min.; uv, 254 nm)
  2. customto provide
  3. customa solid (79.7 mg, yield, 24.8%)