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HRID1482123

反应详情

EQUATION

反应方程式

HRID 1482123 的结构方程式

REACTANTS

反应物

2
结构：COC(=O)[C@@H](OC(C)(C)C)c1c(C)c(C(C)O)c2nc3cn2c1N1CCC(C)(CC1)OCCCC[C@H](C)Oc1ccc(F)cc1-c1cccc-3c1
HCID118316356

未命名化合物

结构：Cc1ccc2c(c1)-c1cccc(c1)-c1nc3cc(C)c([C@H](OC(C)(C)C)C(=O)O)c(n3c1Cl)N1CCC(C)(CC1)OCCCC[C@H](C)O2
HCID118332041

未命名化合物

PRODUCTS

生成物

1
结构：Cc1c([C@H](OC(C)(C)C)C(=O)O)c2n3cc(nc3c1C(C)O)-c1cccc(c1)-c1cc(F)ccc1O[C@@H](C)CCCCOC1(C)CCN2CC1
HCID118316358

未命名化合物

收率 66%

PROCEDURE

实验过程

Prepared in 66% yield from methyl(2S)-2-(tert-butoxy)-2-[(22S)-17-fluoro-5-(1-hydroxyethyl)-4,22,28-trimethyl-21,27-dioxa-1,7,34-triazahexacyclo[26.2.2.16,9.110,14.02,7.015,20]tetratriaconta-2,4,6(34),8,10(33),11,13,15(20),16,18-decaen-3-yl]acetate following the procedure for (2S)-2-(tert-butoxy)-2-[(22S)-8-chloro-4,17,22,28-tetramethyl-21,27-dioxa-1,7,34-triazahexacyclo[26.2.2.16,9.110,14.02,7.015,20]tetratriaconta-2,4,6(34),8,10(33),11,13,15(20),16,18-decaen-3-yl]acetic acid. 1H NMR (400 MHz, DMSO-d6) δ 8.16 (s, 1H), 8.07 (d, J=7.8 Hz, 1H), 7.98 (s, 1H), 7.54 (t, J=7.8 Hz, 1H), 7.36 (d, J=7.8 Hz, 1H), 7.22 (dd, J=9.4, 2.6 Hz, 1H), 7.19-7.14 (m, 2H), 6.15 (br. s., 1H), 5.78 (br. s., 1H), 5.46 (br. s., 1H), 4.62 (br. s., 1H), 3.90-3.79 (m, 1H), 3.62-3.52 (m, 1H), 3.50-3.40 (m, 3H), 2.66 (d, J=9.0 Hz, 1H), 2.40 (s, 3H), 1.95-1.52 (m, 10H), 1.49 (d, J=6.8 Hz, 3H), 1.20 (s, 3H), 1.14 (s, 9H), 1.08 (d, J=6.0 Hz, 3H); LCMS (ESI, M+1): 688.3.