HRID1516061

反应详情

EQUATION

反应方程式

HRID 1516061 的结构方程式

AUXILIARIES

试剂、催化剂与溶剂

2

PROCEDURE

实验过程

To a solution of the product of Example 7A (505 mg, 2.447 mmol) in THF (19 mL) at 0° C. was added a 1M solution (in THF) of lithium aluminum hydride (12.2 mL, 12.237 mmol) dropwise. After completion of addition the ice bath was removed and the reaction was stirred at room temperature for 1 hour under nitrogen atmosphere. Then, in succession, was added water (183 μL), 15% NaOH solution (183 μL), and water (548 μL). The reaction stirred for an additional 15 minutes before it was filtered and washed with THF. The filtrate was then concentrated under reduced pressure to obtain 4-(4-hydroxymethyl-phenyl)butan-2-ol as a brown oil (314 mg, 71% yield). Then to a solution of 2-tert-butyl-4-chloro-5-hydroxy-2H-pyridazin-3-one (234 mg, 1.155 mmol) in THF (45 mL) was added 4-(4-hydroxymethylphenyl)butan-2-ol (312 mg, 1.732 mmol), triphenylphosphine (454 mg, 1.732 mmol), and then diisopropyl azodicarboxylate (DIAD, 335 μL, 1.732 mmol). The reaction was stirred at room temperature overnight under nitrogen atmosphere. Thin layer chromatography (100% ethyl acetate) indicated consumption of the pyridazinone starting material and the reaction was concentrated. The crude material was purified by flash column chromatography (4:1 hexane:ethyl acetate to 100% ethyl acetate) to obtain a clear oil (200 mg, 48% yield). 1H NMR (600 MHz, CDCl3); δ 7.73 (s, 1H), 7.32 (d, 2H, J=8.0), 7.24 (d, 2H, J=8.0), 5.30 (s, 1H), 5.27 (s, 2H), 3.83 (m, 1H), 2.80-2.76 (m, 1H), 2.71-2.66 (m, 1H), 1.63 (s, 9H), 1.23 (d, 3H, J=6.2); 13C(CDCl3 159.3, 153.9, 143.2, 132.5, 129.2, 127.6, 125.4, 150 MHz): δ HRMS calcd for C118.5, 73.4, 67.6, 66.6, 40.9, 32.0, 28.1, 23.9.19H25ClN2O3: 365.162647, found 365.1624.

WORKUP

后处理

  1. customconsumption of the pyridazinone starting material
  2. concentrationthe reaction was concentrated
  3. customThe crude material was purified by flash column chromatography (4:1 hexane:ethyl acetate to 100% ethyl acetate)