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HRID1630180

反应详情

EQUATION

反应方程式

HRID 1630180 的结构方程式

REACTANTS

反应物

2
结构：Cl.O=C(O)Cn1cncn1
HCID44887050

1H-1,2,4-Triazole-1-acetic acid, monohydrochloride

C4H6ClN3O2

结构：N[C@@H](COCc1ccccc1Cl)C(=O)Nc1ccc(Oc2ccc(F)cc2)cc1
HCID67009578

未命名化合物

PRODUCTS

生成物

1
结构：O=C(Cn1cncn1)N[C@@H](COCc1ccccc1Cl)C(=O)Nc1ccc(Oc2ccc(F)cc2)cc1
HCID67009362

未命名化合物

收率 50%

PROCEDURE

实验过程

Proceeding as in Example 1, but substituting 2-(1H-1,2,4-triazol-1-yl)acetic acid hydrochloride and (S)-2-amino-3-(2-chlorobenzyloxy)-N-(4-(4-fluorophenoxy)phenyl)propanamide, gave Compound 181, (S)-2-(2-(1H-1,2,4-triazol-1-yl)acetamido)-3-(2-chlorobenzyloxy)-N-(4-(4-fluorophenoxy)phenyl)propanamide (100 mg, 50%). 1H-NMR (400 MHz, CDCl3): δ 8.40 (s, 1H), 8.20 (s, 1H), 8.00 (s, 1H), 7.50-7.25 (m, 7H), 7.15-6.90 (m, 6H), 5.00 (s, 2H), 4.79-4.60 (m, 3H), 4.00 (m, 1H), 3.70-3.60 (m, 1H). MS (EI) for C26H23ClFN5O4 found 524 (MH+).