HRID1642580

反应详情

EQUATION

反应方程式

HRID 1642580 的结构方程式

PROCEDURE

实验过程

The title compound was prepared from Compound 225 by using an analogous procedure to that outlined in the preparation of Compound 64. 1H NMR (400 MHz, Methanol-d4) δ 8.36 (s, 1 H) 8.12 (s, 1 H) 8.08 (m, 1 H) 7.97 (m, 1 H) 7.88 (t, J=7.84 Hz, 1 H) 7.69 (s, 1 H) 7.21 (d, J=8.32 Hz, 1 H) 7.16 (d, J=8.32 Hz, 1 H) 4.65 (m, 2 H) 4.42 (t, J=6.08 Hz, 2 H) 4.14 (q, J=7.32Hz, H) 3.36 (q, J=7.6 Hz, 2 H) 2.39 (m, 2 H) 1.55 (d, J=7.32 Hz, 3 H) 1.33 (t, J=7.6 Hz, 3 H). [M+H] calc'd for C25H27ClN3O5S, 516; found, 516.