Hydrochloric Acid → 1-Methyl-5(3-methyl-1,2,4-oxadiazol-5-yl)-1,4,5,6-tetrahydropyrimidine HCl

HRID 1653729Notes

Reaction equation

HRID 1653729 reaction equation
[I-].C[NH+:3]1[CH2:8][CH:7]([C:9]2[O:13][N:12]=[C:11]([CH3:14])[N:10]=2)[CH2:6][N:5]([C:15](C2C=CC=CC=2)(C2C=CC=CC=2)C2C=CC=CC=2)[CH2:4]1.[ClH:34]>C(O)(C(F)(F)F)=O>[ClH:34].[CH3:15][N:5]1[CH2:6][CH:7]([C:9]2[O:13][N:12]=[C:11]([CH3:14])[N:10]=2)[CH2:8][N:3]=[CH:4]1

Participants

4

Reactant 2

HCID 313Hydrochloric AcidHCID 703426091-Methyl-3-triphenylmethyl-5(3-methyl-1,2,4-oxadiazol-5-yl)-1,4,5,6-tetrahydropyrimidinium Iodide

Product 1

HCID 703429651-Methyl-5(3-methyl-1,2,4-oxadiazol-5-yl)-1,4,5,6-tetrahydropyrimidine HCl

Reagents, catalysts & solvents 1

HCID 6422Trifluoroacetic acidSolvent2×

Procedure

1-Methyl-3 -triphenylmethyl-5(3-methyl-1,2,4-oxadiazol-5-yl)-1,4,5,6-tetrahydropyrimidinium Iodide (330 mg, 0.6 mmol) was dissolved in TFA (1 mL) with stirring in a stoppered round bottom flask at room temperature. After 18 hours stirring the excess TFA was evaporated in vacuo, and the dark residue triturated with ether. The ether was decanted leaving an oily residue that was taken up in ice cold sat. Na2CO3 and then extracted with chloroform. After drying and evaporation the chloroform fraction gave the free base which was converted to its HCl salt and recrystallized (methanol/ether) to yellow crystals 15 mg (12%) identified by 300 MHz nmr and ms m/z=180.

Workup

  1. customwas evaporated in vacuo
  2. customthe dark residue triturated with ether
  3. customThe ether was decanted
  4. customleaving an oily residue that
  5. extractionextracted with chloroform
  6. customAfter drying
  7. customevaporation the chloroform fraction
  8. customgave the free base which
  9. customrecrystallized (methanol/ether) to yellow crystals 15 mg (12%)

Sources & evidence

ORD record
ord-6c6e99dba07b4ab4958e920380bf92b3
Source dataset
uspto-grants-1995_04
Patent number
US05403845

Reaction notes

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