HRID1662633

反应详情

EQUATION

反应方程式

HRID 1662633 的结构方程式

PROCEDURE

实验过程

With 300 mg of the compound obtained in Step 47-1 and 201 mg of 4-methoxy-2-(trifluoromethoxy)benzene sulfonyl chloride as starting materials, 410 mg of free form of the title compound (pale yellow amorphous) was obtained by a similar method to Example 2. In a similar procedure to Example 43, 383 mg of the obtained free form underwent salt formation and was solidified to obtain 405 mg of the title compound (pale yellow solid).