HRID1712310

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID9032

Potassium cyanide

CKN

结构：COc1ccccc1COCCCOc1ccc(C2CCN(C(=O)OC(C)(C)C)CC2OCCOc2ccccc2CCOS(=O)(=O)c2ccc(C)cc2)cc1

HCID86609986

Tert-butyl 4-{4-[3-(2-methoxybenzyloxy)propoxy]phenyl}-3-(2-{2-[2-(toluene-4-sulphonyloxy)ethyl]phenoxy}-ethoxy)piperidine-1-carboxylate

C44H55NO10S

PRODUCTS

生成物

结构：COc1ccccc1COCCCOc1ccc(C2CCN(C(=O)OC(C)(C)C)CC2OCCOc2ccccc2CCC#N)cc1

HCID68501910

未命名化合物

AUXILIARIES

试剂、催化剂与溶剂

溶剂HCID6228

N,N-Dimethylformamide

C3H7NO

溶剂HCID14798

Sodium Hydroxide

HNaO

PROCEDURE

实验过程

A solution of 0.20 g of tert-butyl 4-{4-[3-(2-methoxybenyloxy)propoxy]phenyl}-3-(2-{2-[2-(toluene-4-sulphonyloxy)ethyl]phenoxy}ethoxy)piperidine-1-carboxylate (Example 26b) and 0.33 g of potassium cyanide in 4 ml of N,N-dimethylformamide is stirred at 65° C. over 10 hours. The reaction mixture is cooled to room temperature, diluted with 0.1N NaOH and extracted with tertbutyl methyl ether (2×) and ethyl acetate. The combined organic phases are dried over sodium sulphate and concentrated by evaporation. The title compound is obtained as a colourless oil from the residue by means of flash chromatography (SiO2 60F). Rf=0.44 (1:1 EtOAc-heptane); Rt=6.02.

WORKUP

后处理

extractionextracted with tertbutyl methyl ether (2×) and ethyl acetate
dry with materialThe combined organic phases are dried over sodium sulphate
concentrationconcentrated by evaporation

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-b9107535701146278257fb0d582fd75d
来源数据集: uspto-grants-2010_09
DOI: 10.6084/m9.figshare.5104873.v1
专利: US07790715B2
来源说明: uspto-grants-2010_09

反应 SMILES

[CH3:1][O:2][C:3]1[CH:56]=[CH:55][CH:54]=[CH:53][C:4]=1[CH2:5][O:6][CH2:7][CH2:8][CH2:9][O:10][C:11]1[CH:16]=[CH:15][C:14]([CH:17]2[CH2:22][CH2:21][N:20]([C:23]([O:25][C:26]([CH3:29])([CH3:28])[CH3:27])=[O:24])[CH2:19][CH:18]2[O:30][CH2:31][CH2:32][O:33][C:34]2[CH:39]=[CH:38][CH:37]=[CH:36][C:35]=2[CH2:40][CH2:41]OS(C2C=CC(C)=CC=2)(=O)=O)=[CH:13][CH:12]=1.[C-:57]#[N:58].[K+]>CN(C)C=O.[OH-].[Na+]>[C:57]([CH2:41][CH2:40][C:35]1[CH:36]=[CH:37][CH:38]=[CH:39][C:34]=1[O:33][CH2:32][CH2:31][O:30][CH:18]1[CH:17]([C:14]2[CH:13]=[CH:12][C:11]([O:10][CH2:9][CH2:8][CH2:7][O:6][CH2:5][C:4]3[CH:53]=[CH:54][CH:55]=[CH:56][C:3]=3[O:2][CH3:1])=[CH:16][CH:15]=2)[CH2:22][CH2:21][N:20]([C:23]([O:25][C:26]([CH3:27])([CH3:28])[CH3:29])=[O:24])[CH2:19]1)#[N:58]