HRID1712331

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID33557

未命名化合物

结构：COc1ccccc1COCCCOc1ccc(C2CCN(C(=O)OC(C)(C)C)CC2OCCOc2ccccc2CCOS(=O)(=O)c2ccc(C)cc2)cc1

HCID86609986

Tert-butyl 4-{4-[3-(2-methoxybenzyloxy)propoxy]phenyl}-3-(2-{2-[2-(toluene-4-sulphonyloxy)ethyl]phenoxy}-ethoxy)piperidine-1-carboxylate

C44H55NO10S

PRODUCTS

生成物

结构：COc1ccccc1COCCCOc1ccc(C2CCN(C(=O)OC(C)(C)C)CC2OCCOc2ccccc2CCN=[N+]=[N-])cc1

HCID86609993

未命名化合物

AUXILIARIES

试剂、催化剂与溶剂

溶剂HCID6228

N,N-Dimethylformamide

C3H7NO

溶剂HCID516892

Sodium Bicarbonate

CHNaO3

PROCEDURE

实验过程

A solution of 2.0 g of tert-butyl 4-{4-[3-(2-methoxybenzyloxy)propoxy]phenyl}-3-(2-{2-[2-(toluene-4-sulphonyloxy)ethyl]phenoxy}ethoxy)piperidine-1-carboxylate (Example 26b) and 1.32 g of sodium azide in 20 ml of N,N-dimethylformamide is stirred at 65° C. over 90 minutes. The reaction mixture is diluted with semisaturated aqueous sodium hydrogencarbonate solution and extracted with tert-butyl methyl ether (3×). The combined organic phases are dried over sodium sulphate and concentrated by evaporation. The crude title compound is obtained as a colourless oil from the residue. Rf=0.43 (1:1 EtOAc-heptane); Rt=6.40.

WORKUP

后处理

extractionextracted with tert-butyl methyl ether (3×)
dry with materialThe combined organic phases are dried over sodium sulphate
concentrationconcentrated by evaporation

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-1e6f41e850894ef8809d0d65a20610e4
来源数据集: uspto-grants-2010_09
DOI: 10.6084/m9.figshare.5104873.v1
专利: US07790715B2
来源说明: uspto-grants-2010_09

反应 SMILES

[CH3:1][O:2][C:3]1[CH:56]=[CH:55][CH:54]=[CH:53][C:4]=1[CH2:5][O:6][CH2:7][CH2:8][CH2:9][O:10][C:11]1[CH:16]=[CH:15][C:14]([CH:17]2[CH2:22][CH2:21][N:20]([C:23]([O:25][C:26]([CH3:29])([CH3:28])[CH3:27])=[O:24])[CH2:19][CH:18]2[O:30][CH2:31][CH2:32][O:33][C:34]2[CH:39]=[CH:38][CH:37]=[CH:36][C:35]=2[CH2:40][CH2:41]OS(C2C=CC(C)=CC=2)(=O)=O)=[CH:13][CH:12]=1.[N-:57]=[N+:58]=[N-:59].[Na+]>CN(C)C=O.C(=O)([O-])O.[Na+]>[N:57]([CH2:41][CH2:40][C:35]1[CH:36]=[CH:37][CH:38]=[CH:39][C:34]=1[O:33][CH2:32][CH2:31][O:30][CH:18]1[CH:17]([C:14]2[CH:13]=[CH:12][C:11]([O:10][CH2:9][CH2:8][CH2:7][O:6][CH2:5][C:4]3[CH:53]=[CH:54][CH:55]=[CH:56][C:3]=3[O:2][CH3:1])=[CH:16][CH:15]=2)[CH2:22][CH2:21][N:20]([C:23]([O:25][C:26]([CH3:27])([CH3:28])[CH3:29])=[O:24])[CH2:19]1)=[N+:58]=[N-:59]