HRID1914332

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID313

Hydrochloric Acid

ClH

HCID14798

Sodium Hydroxide

HNaO

结构：COC(=O)CCNC(=O)c1ccc(C(CC(C)C)Oc2ccc(-c3ccc(C(C)C)cc3)c(C3OCCCO3)c2)cc1

HCID67153581

未命名化合物

PRODUCTS

生成物

结构：CC(C)CC(Oc1ccc(-c2ccc(C(C)C)cc2)c(C=O)c1)c1ccc(C(=O)NCCC(=O)O)cc1

HCID59518153

未命名化合物

结构：COC(=O)CCNC(=O)c1ccc(C(CC(C)C)Oc2ccc(-c3ccc(C(C)C)cc3)c(C=O)c2)cc1

HCID86615986

未命名化合物

AUXILIARIES

试剂、催化剂与溶剂

溶剂HCID8028

Tetrahydrofuran

C4H8O

PROCEDURE

实验过程

3-{4-[1-(2-[1,3]Dioxan-2-yl-4′-isopropyl-biphenyl-4-yloxy)-3-methyl-butyl]-benzoylamino}-propionic acid methyl ester (570 mg) is taken into THF (10 ml), treated with 5N HCl for 5 h, neutralfied with 5N NaOH, extracted with ethyl actate, dried over MgSO4 and concentrated. The residue is purified by column chromatography to afford 3-{4-[1-(2-formyl-4′-isopropyl-biphenyl-4-yloxy)-3-methyl-butyl]-benzoylamino}-propionic acid methyl ester (36 mg) and 3-{4-[1-(2-formyl-4′-isopropyl-biphenyl-4-yloxy)-3-methyl-butyl]-benzoylamino}-propionic acid (228 mg). MS (ES): 502.2 [M+H]+.

WORKUP

后处理

extractionextracted with ethyl actate
dry with materialdried over MgSO4
concentrationconcentrated
customThe residue is purified by column chromatography

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-ef367d5d689c43b0abd47cf275931c20
来源数据集: uspto-grants-2013_12
DOI: 10.6084/m9.figshare.5104873.v1
专利: US08609892B2
来源说明: uspto-grants-2013_12

反应 SMILES

[CH3:1][O:2][C:3](=[O:42])[CH2:4][CH2:5][NH:6][C:7](=[O:41])[C:8]1[CH:13]=[CH:12][C:11]([CH:14]([O:19][C:20]2[CH:25]=[CH:24][C:23]([C:26]3[CH:31]=[CH:30][C:29]([CH:32]([CH3:34])[CH3:33])=[CH:28][CH:27]=3)=[C:22]([CH:35]3OCCC[O:36]3)[CH:21]=2)[CH2:15][CH:16]([CH3:18])[CH3:17])=[CH:10][CH:9]=1.Cl.[OH-].[Na+]>C1COCC1>[CH3:1][O:2][C:3](=[O:42])[CH2:4][CH2:5][NH:6][C:7](=[O:41])[C:8]1[CH:13]=[CH:12][C:11]([CH:14]([O:19][C:20]2[CH:25]=[CH:24][C:23]([C:26]3[CH:31]=[CH:30][C:29]([CH:32]([CH3:33])[CH3:34])=[CH:28][CH:27]=3)=[C:22]([CH:35]=[O:36])[CH:21]=2)[CH2:15][CH:16]([CH3:18])[CH3:17])=[CH:10][CH:9]=1.[CH:35]([C:22]1[CH:21]=[C:20]([O:19][CH:14]([C:11]2[CH:12]=[CH:13][C:8]([C:7]([NH:6][CH2:5][CH2:4][C:3]([OH:42])=[O:2])=[O:41])=[CH:9][CH:10]=2)[CH2:15][CH:16]([CH3:17])[CH3:18])[CH:25]=[CH:24][C:23]=1[C:26]1[CH:31]=[CH:30][C:29]([CH:32]([CH3:34])[CH3:33])=[CH:28][CH:27]=1)=[O:36]