HRID2051757

反应详情

EQUATION

反应方程式

HRID 2051757 的结构方程式

PROCEDURE

实验过程

[II; Ar is 2-Cl-4-CH3OC6H3, Y is O(CH2)8, R is C2H5, R' is CH3CO] was prepared from 0.38 g of lithium hydride, 9.5 g of diethyl acetonylphosphonate and 19.4 g of 8-(2-chloro-4-methoxyphenoxy)octyl iodide according to the procedure of Example 12(b). The product was chromatographed on Florisil to give 5.67 g of diethyl [1-acetyl-9-(2-chloro-4-methoxyphenoxy)nonyl]phosphonate as a light yellow oil; MIC vs. herpes simplex type 2=12 mcg/ml. The NMR spectrum was consistent with the assigned structure.

WORKUP

后处理

  1. customThe product was chromatographed on Florisil