HRID22077

反应详情

EQUATION

反应方程式

HRID 22077 的结构方程式

PROCEDURE

实验过程

Epoxy alcohol 13, 1.4 eq TESOTf, and 1.5 eq of collidine were reacted as in the preparation of 16 to give 95%+yield (<20:1 de) of crude aldehyde 22 which was chromatographed (SiO2, 3% EtOAc/96% Hex/1% TEA) to give 85% of 22. 1H NMR (CDCl3, 500.135 MHz) δ:9.68 (1H, d, J=2.37 Hz), 3.89 (1H, q, J=5.03 Hz), 2.43 (1H, qdd, J=6.95, 5.03, 2.30 Hz), 1.5-1.2 (4H, m), 1.02 (3H, d, J=6.95 Hz), 0.89 (6H, t J=8.0 Hz), 0.85 (3H, t, J=7.14 Hz), and 0.54 (9H, q, J=7.80 Hz). 13C NMR (CDCl3, 90.55 MHz) δ:205.1, 73.3, 51.3, 37.2, 18.1, 14.1, 10.3, 6.4, and 5.1. IR (thin film): 2957 (s), 2938 (s), 2912 (s), 2877 (s), 1726 (s), 1459 (s), 1415 (w), 1379 (w), 1239 (m), 1155 (w), 1074 (s), 1038 (m), 1005 (w), and 741 (s) cm-1. high resolution MS (m/z): 215. 1467, calcd for C11H23O2Si 215.1467 (M-C2H5). [α]D =+14.7° (c=1.89, CH2Cl2). 1H NMR integration of δ 9.69 to δ 9.72 indicated a 90.3:9.7 ratio.

WORKUP

后处理

  1. customto give 95%+