HRID2300623
反应详情
EQUATION
反应方程式
REACTANTS
反应物
PRODUCTS
生成物
PROCEDURE
实验过程
The title compound was prepared (as described above for the preparation of Example 2) from 75 mg (0.18 mmol) of Intermediate 51 and 41 mg (0.18 mmol) of Intermediate 24 to yield 48 mg (43% yield) of Example 3: TLC (DCM/MeOH, 4/1): Rf=0.42; 1H NMR (DMSO-d6, 400 MHz) δ11.5 (d, 1H, J=8.9), 7.95 (d, 2H, J=7.2), 7.77 (d, 2H, J=8.7), 7.72 (d, 2H, J=8.2), 7.1 (d, 2H, J=8.4), 6.97 (d, 2H, J=8.9), 6.79 (d, 2H, J=8.5), 5.58 (s, 1H), 4.65 (m, 1H), 4.11 (t, 2H, J=6.5), 4.1 (m, 1H), 3.16 (dd, 1H, J=13.7, 3.6), 2.84 (t, 2H, J=6.5), 2.74 (dd, 1H, 13.7, 9.0), 2.28 (s, 3H), 1.67 (s, 3H), 1.25 (d, 6H, J=6.0); low resolution MS (ES+)m/e 637.1 (MH+);