HRID2300624
反应详情
EQUATION
反应方程式
REACTANTS
反应物
PRODUCTS
生成物
PROCEDURE
实验过程
The title compound was prepared (as described above for the preparation of Example 2) from 40 mg (0.092 mmol) of Intermediate 50 and 17 mg (0.092 mmol) of Intermediate 16 to yield 21 mg of Example 5: TLC (DCM/MeOH, 4/1): Rf=0.50; 1H NMR (DMSO-d6, 400 MHz) δ11.59 (d, 1H, J=9.8), 8.09 (d, 2H, J=9.0), 7.85 (d, 2H, J=8.8), 7.78 (m, 2H), 7.39 (m, 3H), 7.12 (d, 2H, J=8.0), 6.80 (d, 2H, J=8.0), 5.54 (s, 1H), 4.15 (t, 2H, J=6.6), 4.17 (m, 1H), 3.11 (m, 1H), 2.90 (t, 2H, J=6.6), 2.72 (m, 1H), 2.33 (s, 3H), 1.98 (m, 2H), 0.9 (t, 3H, J=7.5); low resolution MS (ES+)m/e 593.1 (MH+).