HRID2300625

反应详情

EQUATION

反应方程式

HRID 2300625 的结构方程式

PROCEDURE

实验过程

The title compound was prepared (as described above for the preparation of Example 2) from 40 mg (0.092 mmol) of Intermediate 50 and 15 mg (0.092 mmol) of benzoylacetone to yield 32 mg of Example 7: TLC (DCM/MeOH, 4/1): Rf=0.48; 1H NMR (DMSO-d6, 300 MHz) δ11.49 (d, 1H, J=9.8), 8.17 (d, 2h, J=8.9), 7.9 (d, 2H, J=8.9), 7.85 (m, 2H), 7.44 (m, 3H), 7.19 (d, 2H, J=8.8), 6.89 (d, 2H, J=8.8), 5.60 (s, 1H), 4.23 (t, 2H, J=6.0), 4.16 (m, 1H), 3.21 (m, 2H), 2.99 (t, 2H, J=6.0), 2.82 (dd, 1H, J=14.2, 9.8), 2.42 (s, 3H), 1.78 (s, 3H); low resolution MS (ES+)m/e 579.0 (MH+).