HRID2300630
反应详情
EQUATION
反应方程式
REACTANTS
反应物
PRODUCTS
生成物
PROCEDURE
实验过程
The title compound was prepared (as described above for the preparation of Example 2) from 75 mg (0.177 mmol) of Intermediate 51 and 39 mg (0.194 mmol) of Intermediate 32 to yield 70 mg of Example 15: TLC (DCM/MeOH (4:1): Rf=0.55; 1H NMR (DMSO-d6, 300 MHz) δ11.53 (d, 1H, J=9.6), 7.89 (dd, 2H, J=8.8, 5.7), 7.85 (d, 2H, J=8.8), 7.26 (t, 2H, J=8.8), 7.18 (d, 2H, J=8.5), 7.05 (d, 2H, J=8.8), 6.86 (d, 2H, J=8.5), 5.60 (s, 1H), 4.73 (hept, 1H, J=6.0), 4.19 (t, 2H, J=6.7), 4.13 (br s, 1H), 3.19 (m, 1H), 2.92 (t, 2H, J=6.6), 2.80 (dd, 1H, J=14.0, 9.2), 2.36 (s, 3H), 2.07 (m, 2H), 1.34 (d, 6H, J=6.0), 0.99 (t, 3H, J=7.5); low resolution MS (ES+)m/e 601.1 (MH+).