HRID2300644

反应详情

EQUATION

反应方程式

HRID 2300644 的结构方程式

PROCEDURE

实验过程

The title compound was prepared (as described above for the preparation of Example 2) from 100 mg (0.27 mmol) of Intermediate 45 and 58 mg (0.32 mmol) of Intermediate 20 to yield 55 mg of Example 37: TLC (EtOAc/MeOH (7:3): Rf=0.25; 1H NMR (DMSO-d6, 400 MHz) δ11.42 (d, 1H, J=8.93), 7.95 (m. 2H), 7.70 (dd, 1H, J=1.78, 7.69), 7.51 (m, 4H), 7.23 (m, 4H), 6.88 (d, 2H, J=8.50), 5.36 (s, 1H), 4.22 (m, 2H), 4.16 (brs, 1H), 3.18 (m, 1H), 2.94 (m, 2H), 2.84 (m, 1H), 2.40 (s, 3H), 1.70 (s, 3H); low resolution MS (ES−)m/e 545.1 (M-H); RP-HPLC (Vydac C-18, 25 cm×4.6 mm; 30-100% CH3CN in H2O) with 0.1% HCO2H buffer: 30 minutes; 1 mL/min: tr=19.47 min (to=1.43).