HRID2300648

反应详情

EQUATION

反应方程式

HRID 2300648 的结构方程式

PROCEDURE

实验过程

The title compound was prepared (as described above for the preparation of Example 2) from 75 mg (0.18 mmol) of Intermediate 51 and 32 mg (0.194 mmol) of benzoylacetone to yield 55 mg of Example 44: TLC (DCM/MeOH (4:1): Rf=0.50; 1H NMR (DMSO-d6, 400 MHz) δ11.5 (d, 1H, J=9.0), 7.85 (m, 4H), 7.45 (m, 3H), 7.18 (d, 2H, J=8.4); 7.06 (d, 2H, J=8.8), 6.87 (d, 2H, J=8.5), 5.82 (s, 1H), 4.74 (m, 1H), 4.19 (t, 2H, J=6.6), 4.1 (m, 1H), 3.19 (m, 1H), 2.92 (t, 2H, J=6.6), 2.81 (dd, 1H, J=13.9. 9.1), 2.36 (s, 3H), 1.74 (s, 3H), 1.34 (d, 6H, J=6.0); low resolution MS (ES−)m/e 567.2 (M-)