HRID25840

反应详情

EQUATION

反应方程式

HRID 25840 的结构方程式

PROCEDURE

实验过程

452 mg (1.35 mmol) 4-(2-Cyanoethyl)-2-isobutylphenyl-trifluormethanesulfonate (6), 637.8 mg (1.70 mmol, 1.26 eq.) 2-(4-Methoxy-3-naphthalen-1-ylmethyl-phenyl)-4,4,5,5-tetramethyl-[1,3,2]dioxaborolane (64) and 236.8 mg (205 μmol, 0.15 eq.) Pd(Ph3P)4 were dissolved in 20 ml DME/EtOH (9+1). To this yellow solution 1.35 ml (2.70 mmol, 2 eq.) of a 2 M aq. Na2CO3-solution was added and the resulting mixture was heated at 80° C. for 15 h. After concentrating the mixture in vacuo the residue was taken up in water and extracted with CH2Cl2. The comb. org. fractions were dried over MgSO4 and evaporated. Column chromatography (hexanes/EtOAc (3+1)) yielded 513.8 mg (1.19 mmol, 87.78%) 3-(2-Isobutyl-4′-methoxy-3′-naphthalen-1-ylm Rf (hexanes/EtOAc (3+1))=0.40. 1H-NMR (500 MHz, CDCl3): δ=0.51 (d, 6H, J=6.62 Hz, 2*CH3), 1.42 (m, 1H, CH), 2.17 (d, 2H, J=7.25 Hz, CH2), 2.56 (t, 2H, J=7.41 Hz, CH2CH2CN), 2.87 (t, 2H, J=7.41 Hz, CH2CH2CN), 3.91 (s, 3H, OCH3), 4.42 (s, 2H, CH2Naphthyl), 6.71 (d, 1H, J=2.21 Hz), 6.94 (m, 3H), 7.00 (d, 1H, J=7.72 Hz), 7.04 (dd, 1H, J1=8.36 Hz, J2=2.36 Hz), 7.22 (m, 1H), 7.35 (m, 1H), 7.41 (m, 2H), 7.69 (d, 1H, J=8.20 Hz), 7.81 (m, 1H), 7.97 (m, 1H). MS (EI): m/z=434 (16), 433 (48), 336 (9), 335 (56), 294 (11), 293 (83), 292 (17), 277 (9), 265 (20), 264 (100), 253 (29). HR-MS (EI): Calcd. for C31H31NO: 433.240564. Found: 433.241264.