HRID258579

反应详情

EQUATION

反应方程式

HRID 258579 的结构方程式

PROCEDURE

实验过程

In the same manner but replacing 2-phenyl-4-(β-hydroxyethyl)thiazole with an equivalent amount of 2-(4-chlorophenyl)-4-(β-hydroxyethyl)thiazole the intermediate ester, ethyl 6,7-dihydro-4-ethyl-2-(4chlorophenyl)-4H-pyrano[4,3-d]thiazole-4-acetate (IV, R1 = Cl, R2 = CH2CH3, A= COOCH2CH3 and n= 1is obtained. Alkaline hydrolysis of the latter ester gives 6,7-dihydro-4-ethyl-2-(4-chlorophenyl)-4H-pyrano[4,3-d]thiazole-4-acetic acid (I; R1 = Cl, R2 = CH2CH3, R3 = COOH and n= 1), mp 190°-191° C., after crystallization from methanol. The ether extract obtained from the alkaline aqueous solution is purified to give the by-products 6,7-dihydro-4-ethyl-4-methyl-2-(4-chlorophenyl)-4H-pyrano[4,3-d]thiazole hydrochloride, mp 153°-154° C., after trituration with ether containing hydrogen chloride.

WORKUP

后处理

  1. customA= COOCH2CH3 and n= 1is obtained