HRID55008
反应详情
EQUATION
反应方程式
REACTANTS
反应物
PRODUCTS
生成物
PROCEDURE
实验过程
The procedure similar to that described in Example 1 was repeated, except that 334.6 mg (0.7 mmol) of Compound 24 was used and butyl iodide was used in place of methyl iodide. As a result, 228.9 mg (yield: 61%) of Compound 4 was obtained as pale yellow crystals.