HRID586255

反应详情

EQUATION

反应方程式

HRID 586255 的结构方程式

PROCEDURE

实验过程

This compound was prepared in 29% yield as described in the final paragraph of Example 2, step d, but using 7-bromo-3-tert-butylimidazo[1,2-b][1,2,4]triazine instead of 7-bromo-3-trifluoromethylimidazo[1,2-b][1,2,4]triazine, and using 4-fluoro-3-(pyridin-2-yl)phenylboronic acid instead of 2′-fluoro-5′-(4,4,5,5-tetramethyl-[1,3,2]dioxaborolan-2-yl)biphenyl-2-carbonitrile: 1H NMR (400 MHz, CDCl3) δ 1.50 (9H, s), 7.29-7.33 (2H, m), 7.80 (1H, m), 7.86 (1H, m), 8.07 (1H, m), 8.25 (1H, s), 8.59 (1H, s), 8.66 (1H, dd, J 2.3, 7.4 Hz), 8.77 (1H, m); MS (ES+) m/z 348 M+H]+. Anal. Found: C, 66.95; H, 5.15; N, 19.00%. Required for C20H18FN5.0.75H2O: C, 66.56; H, 5.45; N, 19.41%.

WORKUP

后处理

  1. customThis compound was prepared in 29% yield