反应方程式
ClCC(Cl)=[O:4].[S:6]1[CH:10]=[C:9]2[C:11]([O:13][C:14](=[O:15])[C:8]2=[CH:7]1)=[O:12]>>[S:6]1[CH:10]=[C:9]([C:11]([OH:4])=[O:12])[C:8]([C:14]([OH:13])=[O:15])=[CH:7]1参与物
3
实验过程
A 25.5 g. portion of 3,4-thiophenedicarboxylic acid {prepared by the method of Kornfeld and Jones [J. Org. Chem., 19, 1671 (1954)]} is suspended in 50 ml. of chloroacetyl chloride and is heated at reflux for 5.5 hours. Excess chloroacetyl chloride is distilled under reduced pressure. The residue is poured into 100 ml. of water and the resulting crystals are collected to yield 16.1 g. of 3,4-thiophenedicarboxylic anhydride.
后处理
- temperatureat reflux for 5.5 hours
- distillationExcess chloroacetyl chloride is distilled under reduced pressure
- additionThe residue is poured into 100 ml
- customof water and the resulting crystals are collected
- customto yield 16.1 g
来源与证据
- ORD记录
- ord-cdd40e584b9e4651ba74e24770d441ee
- 来源数据集
- uspto-grants-1981_03
- 专利号
- US04259476
关联笔记
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