对氯苯乙酰腈 → HCID 178434323，化合物

HRID 1474447

反应方程式

HRID 1474447 反应方程式
[F:1][C:2]1[CH:10]=[C:9]2[C:5]([C:6]([CH3:11])=[N:7][NH:8]2)=[CH:4][C:3]=1[CH:12]=O.[Cl:14][C:15]1[CH:20]=[CH:19][C:18]([C:21](=[O:25])[CH2:22][C:23]#[N:24])=[CH:17][CH:16]=1>>[Cl:14][C:15]1[CH:16]=[CH:17][C:18]([C:21](/[C:22](=[CH:12]/[C:3]2[CH:4]=[C:5]3[C:9](=[CH:10][C:2]=2[F:1])[NH:8][N:7]=[C:6]3[CH3:11])/[C:23]#[N:24])=[O:25])=[CH:19][CH:20]=1

参与物

3

反应物 2

HCID 138308对氯苯乙酰腈HCID 178434325HCID 178434325，化合物

产物 1

HCID 178434323HCID 178434323，化合物

实验过程

Following the procedure described for Example 2A, the title compound was prepared using 500 mg (2.81 mmol) 6-fluoro-3-methyl-1H-indazole-5-carbaldehyde (Example 3A) and 566 mg (3.09 mmol) 3-(4-chlorophenyl)-3-oxopropanenitrile to yield 830 mg (66% of th.) of the crude product (76% purity) which was used in the next step without further purification.

来源与证据

ORD记录
ord-cd03ffae62884aea9ce0b0eed8fed7ae
来源数据集
uspto-grants-2015_04
专利号
US09018234B2

关联笔记

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