反应方程式
N[C:2]1[CH:11]=[C:10](S(O)(=O)=O)[CH:9]=[C:8]2[C:3]=1[C:4]([OH:20])=[CH:5][C:6](S(O)(=O)=O)=[CH:7]2.ClC1N=C(Cl)N=C(Cl)N=1>>[CH:10]1[CH:11]=[CH:2][C:3]2[C:8](=[CH:7][CH:6]=[CH:5][C:4]=2[OH:20])[CH:9]=1参与物
3
实验过程
In an aqueous solvent, 31.9 parts of 5-amino-4-hydroxynaphthalene-2,7-disulfonic acid was condensed with 18.4 parts of 2,4,6-trichloro-s-triazine according to a normal method and the resultant condensate was condensed with 28.1 parts of 3-(2-sulfate ethylsulfonyl)aniline according to a normal method to obtain a naphthol derivative.
来源与证据
- ORD记录
- ord-4831ffbc507f46cfb8af27025dc7b589
- 来源数据集
- uspto-grants-2000_01
- 专利号
- US06015885
关联笔记
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