Sodium Iodide → 4-Fluorophenyl-1-iodopropane

Beteiligte Stoffe

Reaktionsschritte

The obtained 4-fluorophenylpropan-1-ol (4.83 g, 31.3 mmol) was dissolved in dichloromethane (50 ml), and triethylamine (6.55 ml, 47.0 mmol) and methanesulfonyl chloride (2.91 ml, 37.6 mmol) were added thereto in the ice bath followed by stirring under a nitrogen atmosphere for 30 minutes. The reaction mixture was diluted with dichloromethane (50 ml), and washed with 10% hydrochloric acid and subsequently with a saturated aqueous sodium chloride solution, and then dried over magnesium sulfate. The solvent was evaporated in vacuo, and the residue was dissolved in acetone (100 ml), and then sodium iodide (9.39 g, 62.6 mmol) was added thereto followed by stirring under a nitrogen atmosphere for 2 hours at 50° C. The reaction mixture was diluted with ethyl acetate (250 ml), and washed with 10% aqueous sodium thiosulfate solution and subsequently with a saturated aqueous sodium chloride solution, and then dried over magnesium sulfate. The solvent was evaporated in vacuo, and the residue was purified by flash chromatography on a silica gel column (elution solvent; hexane:ethyl acetate=5:1-2:1) to afford 4-fluorophenyl-1-iodopropane (7.12 g, 86% yield) as a yellow oil.

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