Sodium Iodide → 5-(N,N-Dimethylthiocarbamoyl)thio-4-methyl-2-phenyl-4-isothiazolin-3-one

Beteiligte Stoffe

Reaktionsschritte

To a solution of 4.51 g. (0.02 mole) of 5-chloro-4-methyl-2-phenyl-4-isothiazolin-3-one in 30 ml of warm ethanol was added a solution of 3.58 g. (0.02 mole) of N,N-dimethyldithiocarbamic acid, sodium salt dihydrate in 20 ml of ethanol followed by 0.1 g. of sodium iodide. The mixture was stirred several hours, cooled and filtered. The solid was triturated with water and dried to give 5.3 g. (88%) of the named product, mp 158°-160°.

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