[S:1]1[CH:5]=[CH:4][C:3](B(O)O)=[CH:2]1.[CH2:9](Br)[C:10]1[CH:15]=[CH:14][CH:13]=[CH:12][CH:11]=1>>[CH2:9]([C:3]1[CH:4]=[CH:5][S:1][CH:2]=1)[C:10]1[CH:15]=[CH:14][CH:13]=[CH:12][CH:11]=13-benzylthiophene was prepared in the same manner as described in Example 32C using 3-thienylboronic acid and benzyl bromide, 74% yield.
Wird geladen…