[OH-].[Na+].[CH:3]1[CH:18]=[CH:17][CH:16]=[C:15]2[C:4]=1[CH2:5][C:6]1[C:14]3[CH:13]=[CH:12][CH:11]=[CH:10][C:9]=3[NH:8][C:7]=12.[CH3:19]I>[Br-].C[N+](C)(C)CCCCCCCCCCCCCCCC.C1C=CC=CC=1>[CH3:19][N:8]1[C:9]2[CH:10]=[CH:11][CH:12]=[CH:13][C:14]=2[C:6]2[CH2:5][C:4]3[C:15]([C:7]1=2)=[CH:16][CH:17]=[CH:18][CH:3]=3In a 0.5 l bulb were placed 100 ml 50% aqueous NaOH, 100 ml benzene, 6.1 g (28 mmol)of 5,10-dihydroindeno[1,2-b]indole, prepared in the Example 1,1.8 ml (28 mmol) of MeI and o.5 g of trimethylcetylammonium bromide. After having stirred the obtained mixture for 2 hours, the formation of an organic phase was observed; said phase was separated, washed twice with water (100 ml) and dried over Na2SO4. After removal of the solvent, the residue was recrystallized from ethanol, obtaining 5.3 g of N-methyl-5,10-dihydroindeno[1,2-b]indole(yield=84%).
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