Hydrochloric Acid → 6-Chloro-5-methoxynicotinic acid
Reaktionsgleichung
C[O:2][C:3](=[O:13])[C:4]1[CH:9]=[C:8]([O:10][CH3:11])[C:7]([Cl:12])=[N:6][CH:5]=1.[OH-].[Na+].Cl>CO>[Cl:12][C:7]1[C:8]([O:10][CH3:11])=[CH:9][C:4]([C:3]([OH:13])=[O:2])=[CH:5][N:6]=1Komponenten
5
Edukt 3
Produkt 1
Reagenzien, Katalysatoren, Lösungsmittel 1
Versuchsvorschrift
To a solution of 6-chloro-5-methoxynicotinic acid methyl ester (1.3 g, 6.4 mmol) in MeOH (4 mL) at 25° C. was added 10% NaOH aqueous solution (19.3 mmol). The reaction was stirred for 24 h, then placed into an ice water bath and acidified with 2M HCl until pH=2 was achieved. The flask was then placed into a refrigerator for 3 h. The white precipitate was filtered off and rinsed with cold H2O. The solid was dissolved in acetone, dried over MgSO4 and concentrated to furnish the product 6-chloro-5-methoxynicotinic acid as a yellow solid (0.895 g, 74%); 1H NMR (400 MHz, CDCl3) δ 8.45 (d, 1H), 7.66 (d, 1H), 3.83 (s, 3H).