Pentaerythritol Tetranitrate → Pentolite
Reaktionsgleichung
[CH3:1][C:2]1[C:7]([N+:8]([O-:10])=[O:9])=[CH:6][C:5]([N+:11]([O-:13])=[O:12])=[CH:4][C:3]=1[N+:14]([O-:16])=[O:15].[CH2:17]([O:34][N+:35]([O-:37])=[O:36])[C:18]([CH2:29][O:30][N+:31]([O-:33])=[O:32])([CH2:24][O:25][N+:26]([O-:28])=[O:27])[CH2:19][O:20][N+:21]([O-:23])=[O:22]>>[CH2:29]([O:30][N+:31]([O-:33])=[O:32])[C:18]([CH2:19][O:20][N+:21]([O-:23])=[O:22])([CH2:17][O:34][N+:35]([O-:37])=[O:36])[CH2:24][O:25][N+:26]([O-:28])=[O:27].[CH3:1][C:2]1[C:7]([N+:8]([O-:10])=[O:9])=[CH:6][C:5]([N+:11]([O-:13])=[O:12])=[CH:4][C:3]=1[N+:14]([O-:16])=[O:15]Komponenten
3
Reaktionsbedingungen
- Temperatur
- 95 °C
Versuchsvorschrift
Briefly, a quantity of TNT were added and heated at 95° C. until melting in a reactor provided with a heating jacket and with mechanical stifling. Then, a quantity of PETN were added with a quantity of a gum [e.g., xanthan gum or guar gum] and a quantity of a wax. The components were stirred until achieving a homogeneous mixture which was poured on a cylindrical mold and left to cool, in order to obtain a composition of PETN/TNT/gum/wax with the desired percentage. The cylinders thus obtained are submersed in water at room temperature (18-22° C.) and the effect obtained on the integrity of the cylinder is determined at different times. More information can be found on Example 14].