Ethyl iodoacetate → [2-(2-Chloro-phenyl)-ethoxy]-acetic acid ethyl ester
Reaktionsgleichung
[Cl:1][C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][C:3]=1[CH2:8][CH2:9][OH:10].I[CH2:12][C:13]([O:15][CH2:16][CH3:17])=[O:14].C(C1C=CC=C(C(C)(C)C)N=1)(C)(C)C>FC(F)(F)S([O-])(=O)=O.[Ag+]>[CH2:16]([O:15][C:13](=[O:14])[CH2:12][O:10][CH2:9][CH2:8][C:3]1[CH:4]=[CH:5][CH:6]=[CH:7][C:2]=1[Cl:1])[CH3:17]Komponenten
5
