Sodium Hydroxide → Tyr-Ala-Ala
Reaktionsgleichung
[NH2:1][C@H:2]([C:11]([O:13]C)=O)[CH2:3][C:4]1[CH:9]=[CH:8][C:7]([OH:10])=[CH:6][CH:5]=1.[NH2:15][C@H:16]([C:18]([NH:20][C@H:21]([C:23]([OH:25])=[O:24])[CH3:22])=[O:19])[CH3:17].[OH-].[Na+]>>[NH2:1][C@H:2]([C:11]([NH:15][C@H:16]([C:18]([NH:20][C@H:21]([C:23]([OH:25])=[O:24])[CH3:22])=[O:19])[CH3:17])=[O:13])[CH2:3][C:4]1[CH:5]=[CH:6][C:7]([OH:10])=[CH:8][CH:9]=1Komponenten
4
Versuchsvorschrift
0.2 ml of aqueous solution containing 2 mM Mal-Tyr-OMe, 50 mM H-Ala-Ala-OH, 25 mM NaOH and 0.3 M α-chymotrypsin are deep-frozen. Subsequently the reaction mixture is kept at -25° C. until the Mal-Tyr-OMe is consumed. Following thawing, the yield is determined analytically by RP-HPLC and amounts to 94% of theory.
Aufarbeitung
- temperatureare deep-frozen
- customis consumed