1-Fluoro-2-nitrobenzene → (4-Benzyl-phenyl)-(2-nitro-phenyl)-amine
Reaktionsgleichung
F[C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][C:3]=1[N+:8]([O-:10])=[O:9].[CH2:11]([C:18]1[CH:24]=[CH:23][C:21]([NH2:22])=[CH:20][CH:19]=1)[C:12]1[CH:17]=[CH:16][CH:15]=[CH:14][CH:13]=1.C([O-])(C)(C)C.[K+]>CS(C)=O>[CH2:11]([C:18]1[CH:19]=[CH:20][C:21]([NH:22][C:2]2[CH:7]=[CH:6][CH:5]=[CH:4][C:3]=2[N+:8]([O-:10])=[O:9])=[CH:23][CH:24]=1)[C:12]1[CH:13]=[CH:14][CH:15]=[CH:16][CH:17]=1Komponenten
5
Edukt 3
Produkt 1
Reagenzien, Katalysatoren, Lösungsmittel 1
Versuchsvorschrift
The product (621 mg) is obtained according to the method of stage 1 of Example 4, by using 958 μL of 2-fluoro-nitrobenzene and 2 g of 4-benzylaniline in the presence of 1.63 of potassium tert-butanolate in 30 mL of DMSO.