Hydrochloric Acid → Phenylthiourea

Reaktionsgleichung

[NH2:1][C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][CH:3]=1.[C:8]([SH:10])#[N:9].N.S(=O)(O)[O-].[Na+].Cl>>[C:2]1([NH:1][C:8]([NH2:9])=[S:10])[CH:7]=[CH:6][CH:5]=[CH:4][CH:3]=1

Komponenten

Edukt 4

HCID 313Hydrochloric Acid

HCID 6115Aniline

HCID 13417437Amthio

HCID 23665763Sodium Bisulfite

Produkt 1

HCID 676454Phenylthiourea

Reaktionsbedingungen

Temperatur: 80 °C

Versuchsvorschrift

558 Parts of aniline, 479 parts of ammonium rhodanide and 78 parts of a 40% aqueous sodium bisulfite solution are introduced successively into 592 parts of a 37% aqueous hydrochloric acid. This reaction mixture is at first stirred for 8 hours at 80° C., then for 8 hours at 90° C., thereafter cooled to 20° C.; the precipitate formed is filtered off with suction, washed until neutral and dried. 888 Parts (corresponding to 97.4% of the theory) of phenyl thiourea are obtained, which product has a melting point in the range of from 148° to 150° C.