Reaktionsgleichung
[CH3:1][N:2]1[C:10]2[C:5](=[CH:6][CH:7]=[CH:8][CH:9]=2)[C:4]([CH2:11][CH:12]([CH3:14])[CH3:13])=[C:3]1[C:15]([NH:17][C@H:18]([C:22]([NH:24][CH:25]([C:34](=[O:37])[CH2:35]Br)[CH2:26][C:27]([O:29][C:30]([CH3:33])([CH3:32])[CH3:31])=[O:28])=[O:23])[CH:19]([CH3:21])[CH3:20])=[O:16].[F-].[K+].[F:40][C:41]1[CH:46]=[CH:45][C:44]([OH:47])=[CH:43][CH:42]=1.CCCCCC.CCOC(C)=O>CN(C=O)C>[CH3:1][N:2]1[C:10]2[C:5](=[CH:6][CH:7]=[CH:8][CH:9]=2)[C:4]([CH2:11][CH:12]([CH3:14])[CH3:13])=[C:3]1[C:15]([NH:17][C@H:18]([C:22]([NH:24][CH:25]([C:34](=[O:37])[CH2:35][O:47][C:44]1[CH:45]=[CH:46][C:41]([F:40])=[CH:42][CH:43]=1)[CH2:26][C:27]([O:29][C:30]([CH3:33])([CH3:32])[CH3:31])=[O:28])=[O:23])[CH:19]([CH3:21])[CH3:20])=[O:16]Komponenten
6
Edukt 4
Produkt 1
Reagenzien, Katalysatoren, Lösungsmittel 1
Versuchsvorschrift
The titled product (72 mg, 100%) was prepared as a white solid as described in Example 82 using the product of Example 81 (68.0 mg, 0.12 mmol), potassium fluoride (15.6 mg, 0.27 mmol), and 4-fluorophenol (13.4 mg, 0.12 mmol) in DMF (2.0 ml) TLC (hexane/EtOAc, 50/50): Rf=0.48.
Quellen und Nachweise
- ORD-Eintrag
- ord-94529e0aeb8b4961b8616742d674b5ca
- Quelldatensatz
- uspto-grants-2002_12
- Patentnummer
- US06489353B2
Verknüpfte Notizen
Wird geladen…