O[C:2]1[N:7]=[C:6]2[C:8]3[CH:9]=[CH:10][CH:11]=[CH:12][C:13]=3[C:14](=[O:15])[C:5]2=[N:4][C:3]=1[C:16]#[N:17].O=P(Cl)(Cl)[Cl:20]>>[Cl:20][C:2]1[N:7]=[C:6]2[C:8]3[CH:9]=[CH:10][CH:11]=[CH:12][C:13]=3[C:14](=[O:15])[C:5]2=[N:4][C:3]=1[C:16]#[N:17]A suspension of 6 (671 mg, 3.0 mmol) in POCl3 (8.4 ml) was heated under stirring to 100° C. for 17 h. Excess of POCl3 was evaporated under reduced pressure and the crude was purified by flash chromatography on silica (CH2Cl2), affording 9 (320 mg, 44%) as yellow solid.
Wird geladen…