Sodium borohydride → Methyl (2-hydroxymethyl-5-methylphenoxy)acetate

Beteiligte Stoffe

Reaktionsschritte

By the method of Example 1, Step I, 11.27 g (0.054 mole) of methyl (2-formyl-5-methylphenoxy)acetate was reacted with 0.54 g (0.014 mole) of sodium borohydride and 0.10 g (0.0018 mole) of sodium methoxide in 30 mL of methanol, yielding 9.41 g of methyl (2-hydroxymethyl-5-methylphenoxy)acetate as a yellow oil. The NMR spectrum was consistent with the proposed structure.

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